Yahoo directory vs dmoz?

[pabitra]

Anyone get listed on yahoo directory or dmoz, in your point of view, which is more benefits for rankings a website?

Thanks

 

[SEOPub]

Instead of wasting time worrying over which is better, submit your site to both of them and move on.

They are both good directories.

 

[tk-hassan]

tk-hassan

Yes both are good but how could we manage to get listed on dmoz , do you know any method which really works? and for yahoo directory, it all depends of the person's budget if he can easily afford to pay their fee then it is fine but if he has less budget then he should spend his money to something else rather than having one backlinks even if it is from yahoo directory.

 

[SEOPub]

SEOPub

Yeah it is easy to get listed in Dmoz. You just pay an editor.

 

[seoking]

I know that both are good, but I think dmoz help you to Google & another search engine rankings and yahoo will help you to only yahoo search engine ranking.

 

[PTTed]

Guys, The Yahoo Directory (the original one that you paid to get listed in) has been gone since 2014.

Read this article.

They have the local business directory still, but that is far different and serves a far different purpose for businesses than their original directory did.

 

[rajivsinghi]

Yahoo directory has paid service and if you want to list on DMOZ then website your website should have Page Rank... Because zero page rank or N/a websites are not allowed as per knowledge...

Thanks

 

[SenseiSteve]

SenseiSteve

The original Yahoo Directory cost $300 to be listed, but they no longer exist. See PTTed's earlier reply. Always submit your sites to DMOZ and then wait. Never submit them twice. Good luck.

 

[rf-harris]

If you can afford a link in yahoo directory then it is definitely worth it but when it comes to dmoz it is very hard to get listed on dmoz. It is free but you will be mightily lucky to get an approved listing in dmoz. If I have given a choice whether I would like to be listed on yahoo directory or dmoz then my choice would be dmoz.